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Answer by dfrazzetto (2) ( Show Source ) You can put this solution on YOUR website!Satandard form factored form vertex form any form ***** MATH 45Divide 22\sqrt {y} by 2 The equation is now solved Swap sides so that all variable terms are on the left hand side Factor x^ {2}2x1 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2} Take the square root of

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Y=x^2+2x-8 in vertex form-When graphing the parabola in standard form, to find the vertex we use the following method The xvalue of the vertex is calculated as x = b/(2a) The yvalue of the vertex is f(b/(2a)) The xvalue of the vertex also represents the horizontal shift, while the y Find an answer to your question Write the function in vertex form y=x^26x3 BruhhItsCaroline BruhhItsCaroline Mathematics Middle School answered Write the function in vertex form y=x^26x3 2 See answers znk znk Answer y = 1(x 3)²

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 The equation in vertex form is By looking at the equation we can understand that the y value of the vertex point is 6 By further calculation we can verify that the x value of the vertex point is 3 Now, there are two ways of finding if the vertex point is a maximum or a minimum The first way is picking random x coordinates after andThe axis of symmetry and the vertex of this quadratic function are calculated by hand The results are compared with the results obtained by using a graphing1) y=(x−17)(x2) 2)y=(x−17)(x−2) 3)y=(x−6)2 2 4) y=(x−6)2 −2 6 Which equation and ordered pair represent the correct vertex form and vertex for j(x) =x2 −12x7?

Learn to complete the square in order to write quadratic equations in vertex form Click Create Assignment to assign this modality to your LMS We have a new and improved read on this topicSolving x 22x8 = 0 directly Earlier we factored this polynomial by splitting the middle term let us now solve the equation by Completing The Square and by using the Quadratic Formula Parabola, Finding the Vertex 31 Find the Vertex of y = x 22x8 Parabolas have a highest or a lowest point called the Vertex Vertex Form Of A Quadratic The vertex form of a quadratic is given by y = a(x – h) 2 k, where (h, k) is the vertexThe "a" in the vertex form is the same "a" as in y = ax 2 bx c (that is, both a's have exactly the same value) The sign on "a" tells you whether the quadratic opens up or opens downThink of it this way A positive "a" draws a smiley, and a negative

My initial idea was to take the derivative, and set it to zero y = x^2 8x 10 dy/dx = 2x 8 Setting that to zero gives an x value of 4, and plugging x = 4 into the first equation gives y = 6 Thus, the veQuestion Write y=2x^212x14 in vertex form Answer by jim_thompson5910 () ( Show Source ) You can put this solution on YOUR website!Y = (x 2 2x 8) y = (x 2 2x 8) y = (x 2 2 ⋅ x ⋅1 1 218) y = ((x1) 29) y = (x1) 2 9 By comparing this with the vertex form of parabola, we get (h, k) ==> (1, 9) Example 6 y = (x1)(x3) Solution y = x 24x3 y = x 22 ⋅ x ⋅2 2 22 2 3 y = (x2) 243 y = (x2) 21

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The vertex form is a special form of a quadratic function From the vertex form, it is easily visible where the maximum or minimum point (the vertex) of the parabola is The number in brackets gives (trouble spot up to the sign!) the xcoordinate of the vertex, the number at the end of the form gives the ycoordinate This means If the vertex form is , then the vertex is at (hk) How to put a function into vertex form?While the standard quadratic form is a x 2 b x c = y, the vertex form of a quadratic equation is y = a ( x − h) 2 k In both forms, y is the y coordinate, x is the x coordinate, and a is the constant that tells you whether the parabola is facing up ( a) or down ( − a ) (I think about it as if the parabola was a bowl of applesauce The equation of a parabola in vertex form is ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣ ∣ 2 2y = a(x − h)2 k2 2 ∣∣ ∣ −−−−−−−−−−−−−−−−−−−−− where (h ,k) are the coordinates of the vertex and a is a constant Rearrange y = x2 − 2x into this form using the method of completing the square y = (x2 −2x1)−1 ⇒ y = (x −1)2 − 1 ← in vertex form

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Answer by Edwin McCravy () ( Show Source ) You can put this solution on YOUR website!Write y=2x^24x12 in vertex form 1 See answer shuvt is waiting for your help Add your answer and earn points masonlawiii masonlawiii This is the answer y=2(x1)^28 nope apperently its y=2(x1)^210 New questions in Mathematics In exercise 5 Best Answer For the general quadratic equation \(y=ax^2bxc\) the vertex occurs where \(x_{vertex}=\frac{b}{2a}\) To find the value of y at that point, put this back into the quadratic equation \(y_{vertex}=(\frac{b}{2a})^2b(\frac{b}{2a})c\) In vertex form the quadratic can now be written as \(yy_{vertex}=(xx_{vertex})^2\) See if you can apply this to your

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1) write y=4x^232x66 in vertex form Complete the square y= 4x^32x64 66 64 y= (2x8)^2 2 vertex = 4,2 2)use the quadratic formula to solve the equation 4x^2x3=0A vertical stretch or compression a > 0, the parabola opens up and there is a minimum value a< 0, the parabola opens down and there is a maximum value (may also be referred to as a reflection in the xaxis) 1 y = x² 4x 12 When y = 0 x² 4x 12 = 0 x² 4x 12 = 0 (x 2)(x 6) = 0 x = 2 or x = 6 The xintercepts are 2 and 6 y = (x² 4x) 12 y = (x²

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 Method 1 Converting to Vertex Form Vertex form can be represented as #y=(xh)^2k# where the point #(h,k)# is the vertex To do that, we should complete the square #y=x^22x2# First, we should try to change the last number in a way so we can factor the entire thing #=># we should aim for #y=x^22x1# to make it look like #y=(x1)^2#Free Parabola Vertex calculator Calculate parabola vertex given equation stepbystep This website uses cookies to ensure you get the best experience Convert equation from quadratic form to vertex form, y= a(xh)^2 k, by completing the square y= 25x^255x525 Algebra For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6

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 Explanation y = x2 − 2x 8 or y = (x2 − 2x 1) −1 8 or y = (x − 1)2 7 Comparing with vertex form of equation f (x) = a(x −h)2 k;(h,k) being vertex we find here h = 1,k = 7,a = 1 ∴ Vertex is at (1,7) and vertex form of equation is y = (x − 1)2 7 graph {x^22x8 3554, 3558, 1778, 1778} Ans Answer linkThe quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2xy8=0 x 2 2 x − y − 8 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 2 for b, and 8y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}Learn honors algebra 2 standard form vertex with free interactive flashcards Choose from 303 different sets of honors algebra 2 standard form vertex flashcards on Quizlet

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Free functions vertex calculator find function's vertex stepbystep This website uses cookies to ensure you get the best experience By using this website, you agree to our Cookie PolicyFinding the Vertex Form The required equation for an updown facing parabola is 4p(y−k) = (x−h)2 4 p ( y − k) = ( x − h) 2 and it has vertex (h,k) ( h, k) and the focal length p p InBut the equation for a parabola can also be written in "vertex form" y = a ( x − h) 2 k In this equation, the vertex of the parabola is the point ( h, k) You can see how this relates to the standard equation by multiplying it out y = a ( x − h) ( x − h) k y = a x 2 − 2 a h x a h 2 k This means that in the standard form, y

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Y = x2 − 2x − 8 y = x 2 2 x 8 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 2 x − 8 x 2 2 x 8 Tap for more steps Use the form a x 2 b x👉 Learn how to graph quadratic equations by completing the square A quadratic equation is an equation of the form y = ax^2 bx c, where a, b and c are cFind the Vertex f(x)=x^22x8 Rewrite the equation in term of and Rewrite the equation in vertex form Tap for more steps Complete the square for Substitute the values of , , and into the vertex form Set equal to the new right side Use the vertex form, , to determine the values of , ,

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Start with the given quadratic Subtract from both sides Factor out the leading coefficient This step is important since we want the coefficient to be 1 Take half of the x coefficient to get (ie )Find the Vertex y=1/2x^22x8 Rewrite the equation in vertex form Tap for more steps Combine and Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formulaThe vertex of an equation in vertex form is (h,k), which for our equation is (6,4) Notes Right now our quadratic equation, y=x 2 12x32 is in standard form

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We want to get y = a (xh) k y = x 3x6 in the form Put brackets around the first two terms on the right, y = x 3x6 and since the coefficient of x is 1 put 1 in front of the parentheses Normally you would factor out the coefficient of x y = 1 xThis video screencast was created with Doceri on an iPad Doceri is free in the iTunes app store Learn more at http//wwwdocericomVertex Form Equation & Functions Just as y = mx b is a useful format for graphing linear functions, y = a(x h)^2 k is a useful format for graphing quadratic functions

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 Explanation Changing a quadratic function from standard form to vertex form actually requires that we go through the process of completing the square To do this, we need the x2 and x terms only on the right side of the equation y = x2 2x −8 y 8 = x2 2x −8 8 y 8 = x2 2x −8 8 y 8 = x2 2x** y=x^(2)8x1 complete the square y=(x^28x16)116 y=(x4)^217 This is an equation of a parabola that opens upwards with vertex at (4,17) Its standard form of equationy= (xh)^2k, (h,k) =(x,y) coordinates of the vertexWhat is y=x^(2)8x1 in vertex form?

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Divide 0 0 by − 8 8 Multiply − 1 1 by 0 0 Add 8 8 and 0 0 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a(x−h)2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k To change the expression (x2 2x) into a perfect square trinomial add (half the x coefficient)² to each side of the expression Here x coefficient = 2 So, (half the x coefficient)2 = (2/2)2 = 1 Add and subtract 1 to the expression The vertex form of the parabola with vertex (h, k) and axis of symmetry x = h is y = a (x h)2 k Find the vertex of the function y = –x2 2x 8 It is where the derivative 2x 2 = 0 Since you probably haven't learned about derivatives, do it this way Rewrite is as x^2 2x 8 = (x1)^2 7 Now look at the form of the formula on the right It

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 Convert equation from quadratic form to vertex form, y= a(xh)^2 k, by completing the square y= 25x^255x525 math which form of a quadratic funtion is easiest to use to find the maximum or minimum value of the function? Complete the square to rewrite the quadratic function in vertex form y = x ^ 2 2x 8 Answers 3 Get Other questions on the subject Mathematics Mathematics, 1530, southerntouch103 Gretchen is setting up for a banquet she has 300 chairs and needs to distribute them evenly among t tables how many chairs should she put atAlgebra Find the Vertex Form y=x^22x8 y = x2 − 2x − 8 y = x 2 2 x 8 Complete the square for x2 −2x−8 x 2 2 x 8 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = − 2, c = − 8 a = 1, b = 2, c =

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Because of the symmetry of a parabola, the vertex is found on the vertical line exactly halfway between the roots, so x=3 (you can add the coordinates of the two roots and divide by 2, to find the midpoint of the segment between them) The y value at the vertex is y (3) = 2 (3 – 5) (3 – 1) = − 8 meaning the vertex has the coordinates (3, 8)Plug (1,7) into the equation and define b in terms of a math7=ab8\\b=a1/math (0,8) is a point on the parabola, so by symmetry, (2,8) is also a point Plug (2,8) into the equation and define b in terms of a math8=4a2b8\\b=2a\\/mathStart with y = x^2 8x 2 add 2 to both sides of the equation to get y 2 = x^2 8x complete the square on the expression on the right side of the equation to get y 2 = (x4)^2 16 subtract 2 from both sides of the equation to get y = (x4)^2 18 that's your vertex form

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The two answers below are perfect;Create your account View this answer The given equation is y =x2−2x−8 y = x 2 − 2 x − 8 To convert this into the vertex form, we have to complete the squares Adding 8 8 on both sidesIn vertex form as 1) f(x) =(3x6)2 −25 2) f(x) =3(x6)2 −25 3) f(x) =3(x2)2 −1 4) f(x) =3(x2)2 7 5 Which equation is equivalent to y−34 =x(x−12)?

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